# Aptitude | Probability | Question 7

A bag contains 21 balls numbered 1 to 21. two balls are drawn one after another without replacement. Find the probability that both balls are even numbered.

**(A)** 3/14**(B)** 2/3**(C)** 6/9**(D)** 1/8**Answer:** **(A)****Explanation:**

Total numbers in sample space is 21

Probability of choosing any two of them is 21C2.

There are total 10 even numbers from 1 to 21 and probability of choosing any two of them is 10C2

Therefore the required answer is 10C2/21C2 = 3/14